Mar 20, 2008

SICP Exercise 1.21


(define (smallest-divisor n)
(find-divisor n 2))
(define (find-divisor n test-divisor)
(cond ((> (square test-divisor) n) n)
((divides? test-divisor n) test-divisor)
(else (find-divisor n (+ test-divisor 1)))))
(define (divides? a b)
(= (remainder b a) 0))
(define (square n)
(* n n))



(smallest-divisor 199)
(smallest-divisor 1999)
(smallest-divisor 19999)



199
1999
7

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